std::copy_backward
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Definido no cabeçalho <algorithm>
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template< class BidirIt1, class BidirIt2 > BidirIt2 copy_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); |
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Copia os elementos da gama, definida por
[first, last)
, para outro intervalo terminando no d_last
. Os elementos são copiados em ordem inversa (o último elemento é copiado primeiro), mas a sua ordem relativa é preservada.Original:
Copies the elements from the range, defined by
[first, last)
, to another range ending at d_last
. The elements are copied in reverse order (the last element is copied first), but their relative order is preserved.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Índice |
[editar] Parâmetros
first, last | - | a gama de elementos de copiar
Original: the range of the elements to copy The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
d_last | - | final do intervalo de destino. Se
d_last está dentro [first, last) , std::copy deve ser utilizado em vez de std::copy_backward . Original: end of the destination range. If d_last is within [first, last) , std::copy must be used instead of std::copy_backward. The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Type requirements | ||
-BidirIt must meet the requirements of BidirectionalIterator .
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[editar] Valor de retorno
iterador para o último elemento copiado.
Original:
iterator to the last element copied.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Complexidade
Exatamente
last - first
atribuições.Original:
Exactly
last - first
assignments.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Possível implementação
template< class BidirIt1, class BidirIt2 > BidirIt2 copy_backward(BidirIt1 first, BidirIt1 last, BidirIt2 d_last) { while (first != last) { *(--d_last) = *(--last); } return d_last; } |
[editar] Exemplo
#include <algorithm> #include <iostream> int main() { std::vector<int> from_vector; for (int i = 0; i < 10; i++) { from_vector.push_back(i); } std::vector<int> to_vector(15); std::copy_backward(from_vector.begin(), from_vector.end(), to_vector.end()); std::cout << "to_vector contains: "; for (unsigned int i = 0; i < to_vector.size(); i++) { std::cout << to_vector[i] << " "; } }
Saída:
to_vector contains: 0 0 0 0 0 0 1 2 3 4 5 6 7 8 9
[editar] Veja também
(C++11) |
Copia um intervalo de elementos para um novo local Original: copies a range of elements to a new location The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) |