std::atanh
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Definido no cabeçalho <cmath>
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float atanh( float arg ); |
(desde C++11) | |
double atanh( double arg ); |
(desde C++11) | |
long double atanh( long double arg ); |
(desde C++11) | |
double atanh( Integral arg ); |
(desde C++11) | |
Calcula arco tangente hiperbólico de
arg
Original:
Computes hyperbolic arc tangent of
arg
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You can help to correct and verify the translation. Click here for instructions.
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Índice |
[editar] Parâmetros
arg | - | flutuando valor de ponto
Original: floating point value The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
[editar] Valor de retorno
tangente hiperbólica inversa de
arg
Original:
inverse hyperbolic tangent of
arg
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Veja também
(C++11) |
arco seno hiperbólico Original: hyperbolic arc sine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função) |
(C++11) |
hiperbólica arco cosseno Original: hyperbolic arc cosine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função) |
tangente hiperbólica Original: hyperbolic tangent The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função) | |
(C++11) |
calcula arco tangente hiperbólico de um número complexo Original: computes hyperbolic arc tangent of a complex number The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (modelo de função) |
[editar] Links externos
Weisstein, Eric W. "Inverse Hyperbolic Tangent." De MathWorld - Um recurso Web Wolfram.
Original:
Weisstein, Eric W. "Inverse Hyperbolic Tangent." From MathWorld--A Wolfram Web Resource.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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