Assignment operators
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Operatori di assegnazione modificare il valore dell'oggetto.
Original:
Assignment operators modify the value of the object.
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Operator name | Syntax | Overloadable | Prototype examples (for class T) | |
---|---|---|---|---|
Inside class definition | Outside class definition | |||
basic assignment | a = b
|
Yes | T& T::operator =(const T2& b); | N/A |
move assignment (C++11) | a = rvalue
|
Yes | T& T::operator =(T2&& b); | N/A |
addition assignment | a += b
|
Yes | T& T::operator +=(const T2& b); | T& operator +=(T& a, const T2& b); |
subtraction assignment | a -= b
|
Yes | T& T::operator -=(const T2& b); | T& operator -=(T& a, const T2& b); |
multiplication assignment | a *= b
|
Yes | T& T::operator *=(const T2& b); | T& operator *=(T& a, const T2& b); |
division assignment | a /= b
|
Yes | T& T::operator /=(const T2& b); | T& operator /=(T& a, const T2& b); |
modulo assignment | a %= b
|
Yes | T& T::operator %=(const T2& b); | T& operator %=(T& a, const T2& b); |
bitwise AND assignment | a &= b
|
Yes | T& T::operator &=(const T2& b); | T& operator &=(T& a, const T2& b); |
bitwise OR assignment | a |= b
|
Yes | T& T::operator |=(const T2& b); | T& operator |=(T& a, const T2& b); |
bitwise XOR assignment | a ^= b
|
Yes | T& T::operator ^=(const T2& b); | T& operator ^=(T& a, const T2& b); |
bitwise left shift assignment | a <<= b
|
Yes | T& T::operator <<=(const T2& b); | T& operator <<=(T& a, const T2& b); |
bitwise right shift assignment | a >>= b
|
Yes | T& T::operator >>=(const T2& b); | T& operator >>=(T& a, const T2& b); |
|
Indice |
[modifica] Spiegazione
Copia' assegnazione operatore sostituisce il contenuto del
a
oggetto con una copia del contenuto di b
(b
non viene modificato). Per i tipi di classe, questa è una funzione membro speciale, descritto in copiare operatore di assegnazione.Original:
copy assignment operator replaces the contents of the object
a
with a copy of the contents of b
(b
is no modified). For class types, this is a special member function, described in copiare operatore di assegnazione.The text has been machine-translated via Google Translate.
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Mossa' assegnazione operatore sostituisce il contenuto del
a
oggetto con il contenuto di b
, evitando la copia se possibile (b
può essere modificato). Per i tipi di classe, questa è una funzione membro speciale, descritto in spostare operatore di assegnazione. (dal C++11) Original:
move assignment operator replaces the contents of the object
a
with the contents of b
, avoiding copying if possible (b
may be modified). For class types, this is a special member function, described in spostare operatore di assegnazione. (dal C++11) The text has been machine-translated via Google Translate.
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Per i non-classe tipi, copia e spostamento di assegnazione sono indistinguibili e sono indicati come l'assegnazione diretta.
Original:
For non-class types, copy and move assignment are indistinguishable and are referred to as direct assignment.
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' Operatori composti di assegnazione sostituire il contenuto dei contenuti del
a
oggetto con il risultato di un'operazione binaria tra il valore precedente a
e il valore di b
.Original:
compound assignment operators replace the contents the contents of the object
a
with the result of a binary operation between the previous value of a
and the value of b
.The text has been machine-translated via Google Translate.
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[modifica] Builtin assegnazione diretta
Per ogni tipo di
T
, le firme delle funzioni seguenti partecipare risoluzione di sovraccarico:Original:
For every type
T
, the following function signatures participate in overload resolution:The text has been machine-translated via Google Translate.
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T*& operator=(T*&, T*); |
||
T*volatile & operator=(T*volatile &, T*); |
||
Per ogni enumerazione o puntatore a un membro del tipo
T
, facoltativamente volatili-qualificata, la firma seguente funzione partecipa risoluzione di sovraccarico:Original:
For every enumeration or pointer to member type
T
, optionally volatile-qualified, the following function signature participates in overload resolution:The text has been machine-translated via Google Translate.
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T& operator=(T&, T ); |
||
Per ogni coppia di A1 e A2, dove A1 è un tipo aritmetico (opzionalmente volatili-qualificata) e A2 è un tipo aritmetico promosso, la firma seguente funzione partecipa risoluzione di sovraccarico:
Original:
For every pair A1 and A2, where A1 is an arithmetic type (optionally volatile-qualified) and A2 is a promoted arithmetic type, the following function signature participates in overload resolution:
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A1& operator=(A1&, A2); |
||
Per le espressioni E1 di qualsiasi
T
tipo scalare, le seguenti forme supplementari di espressione di assegnazione builtin sono consentiti:Original:
For expressions E1 of any scalar type
T
, the following additional forms of the builtin assignment expression are allowed:The text has been machine-translated via Google Translate.
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E1 = {} |
(dal C++11) | |
E1 = {E2} |
(dal C++11) | |
Nota: quanto sopra non include tutti i tipi ad eccezione di classe tipi di riferimento, i tipi di array, tipi di funzioni e il void tipo, che non sono direttamente imputabili.
Original:
Note: the above includes all non-class types except reference types, array types, function types, and the type void, which are not directly assignable.
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L'operatore di assegnazione diretta si aspetta un lvalue modificabile come i suoi operando sinistro e restituisce un lvalue che identifica l'operando di sinistra dopo la modifica. Per i non-classe tipi, l'operando di destra è conversione implicita primo al cv-non qualificato tipo di operando di sinistra, e quindi il suo valore viene copiato dentro l'oggetto identificato da operando di sinistra.
Original:
The direct assignment operator expects a modifiable lvalue as its left operand and returns an lvalue identifying the left operand after modification. For non-class types, the right operand is first conversione implicita to the cv-unqualified type of the left operand, and then its value is copied into the object identified by left operand.
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Quando l'operando di sinistra è un tipo di riferimento, l'operatore di assegnazione si applica al-di cui all'oggetto.
Original:
When the left operand is a reference type, the assignment operator applies to the referred-to object.
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Se la sinistra e gli operandi giusti identificare oggetti sovrapposti, il comportamento è indefinito (a meno che la sovrapposizione è esatta e il tipo è lo stesso)
Original:
If the left and the right operands identify overlapping objects, the behavior is undefined (unless the overlap is exact and the type is the same)
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Se l'operando di destra è un rinforzato-init-list
Original:
If the right operand is a braced-init-list
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- la E1 = {} espressione è equivalente a E1 = T(), dove
T
è il tipo diE1
.Original:the expression E1 = {} is equivalent to E1 = T(), whereT
is the type ofE1
.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions. - il E1 = {E2} espressione è equivalente a E1 = T(E2), dove
T
è il tipo diE1
, salvo che conversioni implicite sono vietate.Original:the expression E1 = {E2} is equivalent to E1 = T(E2), whereT
is the type ofE1
, except that narrowing implicit conversions are prohibited.The text has been machine-translated via Google Translate.
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Per i tipi di classe, questa sintassi genera una chiamata l'operatore di assegnamento con std::initializer_list come argomento, seguendo le regole di list-inizializzazione
Original:
For class types, this syntax generates a call to the assignment operator with std::initializer_list as the argument, following the rules of list-inizializzazione
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[modifica] Esempio
#include <iostream> int main() { int n = 0; // not an assignment n = 1; // direct asignment std::cout << n << ' '; n = {}; // zero-initialization, then assignment std::cout << n << ' '; n = 'a'; // integral promotion, then assignment std::cout << n << ' '; n = {'b'}; // explicit cast, then assignment std::cout << n << ' '; n = 1.0; // floating-point conversion, then assignment std::cout << n << ' '; // n = {1.0}; // compiler error (narrowing conversion) int& r = n; // not an assignment int* p; r = 2; // assignment through reference std::cout << n << ' '; p = &n; // direct assignment p = nullptr; // null-pointer conversion, then assignment }
Output:
1 0 97 98 1 2
[modifica] Builtin assegnazione composta
Per ogni coppia di A1 e A2, dove A1 è un tipo aritmetico (opzionalmente volatili-qualificata) e A2 è un tipo aritmetico promosso, le firme delle funzioni seguenti partecipare risoluzione di sovraccarico:
Original:
For every pair A1 and A2, where A1 is an arithmetic type (optionally volatile-qualified) and A2 is a promoted arithmetic type, the following function signatures participate in overload resolution:
The text has been machine-translated via Google Translate.
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A1& operator*=(A1&, A2); |
||
A1& operator/=(A1&, A2); |
||
A1& operator+=(A1&, A2); |
||
A1& operator-=(A1&, A2); |
||
Per ogni coppia di I1 e I2, dove I1 è un tipo integrale (opzionalmente volatili-qualificata) e I2 è un tipo di promozione integrale, le firme delle funzioni seguenti partecipare risoluzione di sovraccarico:
Original:
For every pair I1 and I2, where I1 is an integral type (optionally volatile-qualified) and I2 is a promoted integral type, the following function signatures participate in overload resolution:
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I1& operator%=(I1&, I2); |
||
I1& operator<<=(I1&, I2); |
||
I1& operator>>=(I1&, I2); |
||
I1& operator&=(I1&, I2); |
||
I1& operator^=(I1&, I2); |
||
I1& operator|=(I1&, I2); |
||
Per ogni oggetto
T
opzionalmente cv tipo qualificato, le firme delle funzioni seguenti partecipare risoluzione di sovraccarico:Original:
For every optionally cv-qualified object type
T
, the following function signatures participate in overload resolution:The text has been machine-translated via Google Translate.
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T*& operator+=(T*&, std::ptrdiff_t); |
||
T*& operator-=(T*&, std::ptrdiff_t); |
||
T*volatile & operator+=(T*volatile &, std::ptrdiff_t); |
||
T*volatile & operator-=(T*volatile &, std::ptrdiff_t); |
||
{{{1}}}
Original:
{{{2}}}
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[modifica] Esempio
This section is incomplete Reason: no example |
[modifica] Vedi anche
Common operators | ||||||
---|---|---|---|---|---|---|
assegnazione | incrementNJdecrement | aritmetica | logico | confronto | memberNJaccess | altra |
a = b |
++a |
+a |
!a |
a == b |
a[b] |
a(...) |
Special operators | ||||||
static_cast converte un tipo a un altro
tipo compatibile Original: static_cast converts one type to another compatible type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. dynamic_cast converte classe virtuale di base per class
derivato Original: dynamic_cast converts virtual base class to derived class The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. const_cast converte il tipo di tipo compatibile con diversi cv qualifiers
Original: The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. reinterpret_cast converte tipo type
incompatibile Original: reinterpret_cast converts type to incompatible type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. new alloca memory
Original: new allocates memory The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. delete dealloca memory
Original: delete deallocates memory The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. sizeof interroga la dimensione di un type
Original: sizeof queries the size of a type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. sizeof... interroga le dimensioni di un parametro confezione (dal C++11)
Original: The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. typeid interroga le informazioni sul tipo di una type
Original: typeid queries the type information of a type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. noexcept controlla se un'espressione può lanciare una (dal C++11)
un'eccezione Original: The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. alignof query requisiti di allineamento di un (dal C++11) tipo
Original: alignof queries alignment requirements of a type (dal C++11) The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |