I'm working on a task where I need to convert a byte array obtained from a hexadecimal string into a string representation, utilizing only the specified data type (dtype) in NumPy. Here's what I've tried:
import numpy as np
# Define the data type as a Unicode string of length 1
dt = np.dtype('<S1') # Unicode string of length 1
# Sample data
res = '52'
# Convert the hexadecimal string to a bytearray
buf = bytearray.fromhex(res)
# Create a NumPy array from the list of characters
arr_resp = np.frombuffer(buf, dtype=dt)
print(arr_resp_str)
the consol:
[b'R']
and I want to store it as:
['R']
However, instead of obtaining the string representation of the byte array, the output displays the characters as byte class objects. How can I adjust this code to achieve the string representation using only the NumPy dtype? I don't want to just convert, (like DECODE etc.) but store back the string inside a NUMPY object Your insights and suggestions would be invaluable. Thank you.
print(arr_resp_str[0:])
np.dtype('<S1')
is not unicode. It's one byte. 'U1' is unicode, 4 bytes. (technically unicode is 1-4 bytes, but numpy has to have a consistentitemsize!.
np.array([b'R']).astype('U1')` should do the desired conversion (but probably using string methods under the covers).b'R'
is how python3 displays a byte string. That used to be the standard in python2. Now the default is unicode, which is displayed as'R'
(oru'R'
).store back the string inside a NUMPY object
. The buffer contains one byte, which can be interpreted as 'uint8' or 'S1'. It'can't be a 'U1' character withoutdecode
.