-
Notifications
You must be signed in to change notification settings - Fork 23
/
Copy pathlib.rs
55 lines (49 loc) · 1.15 KB
/
lib.rs
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
//Definition for a binary tree node.
#[derive(Debug, PartialEq, Eq)]
pub struct TreeNode {
pub val: i32,
pub left: Option<Rc<RefCell<TreeNode>>>,
pub right: Option<Rc<RefCell<TreeNode>>>,
}
impl TreeNode {
#[inline]
pub fn new(val: i32) -> Self {
TreeNode {
val,
left: None,
right: None,
}
}
}
// 给定一棵二叉搜索树,请找出其中第k大的节点。
//
// 示例 1:
// 输入: root = [3,1,4,null,2], k = 1
// 3
// / \
// 1 4
// \
// 2
// 输出: 4
use std::cell::RefCell;
use std::rc::Rc;
pub fn kth_largest(mut root: Option<Rc<RefCell<TreeNode>>>, k: i32) -> i32 {
if root.is_none() {
return 0;
}
let mut v = vec![];
let mut stack = vec![];
while stack.len() != 0 || !root.is_none() {
while !root.is_none() {
// 一直添加左子树直到为空
let node = root.unwrap();
root = node.borrow_mut().left.take();
stack.push(node);
}
// 从栈中弹出,取节点的右子树
root = stack.pop();
v.push(root.as_mut().unwrap().borrow().val);
root = root.unwrap().borrow_mut().right.take();
}
return *v.get(v.len() - k as usize).unwrap();
}