forked from fishercoder1534/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path_1385.java
60 lines (59 loc) · 1.55 KB
/
_1385.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
package com.fishercoder.solutions;
/**
* 1385. Find the Distance Value Between Two Arrays
*
* Given two integer arrays arr1 and arr2, and the integer d, return the distance value between the two arrays.
* The distance value is defined as the number of elements arr1[i] such that there is not any element arr2[j] where |arr1[i]-arr2[j]| <= d.
*
* Example 1:
* Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
* Output: 2
* Explanation:
* For arr1[0]=4 we have:
* |4-10|=6 > d=2
* |4-9|=5 > d=2
* |4-1|=3 > d=2
* |4-8|=4 > d=2
* For arr1[1]=5 we have:
* |5-10|=5 > d=2
* |5-9|=4 > d=2
* |5-1|=4 > d=2
* |5-8|=3 > d=2
* For arr1[2]=8 we have:
* |8-10|=2 <= d=2
* |8-9|=1 <= d=2
* |8-1|=7 > d=2
* |8-8|=0 <= d=2
*
* Example 2:
* Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
* Output: 2
*
* Example 3:
* Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
* Output: 1
*
* Constraints:
* 1 <= arr1.length, arr2.length <= 500
* -10^3 <= arr1[i], arr2[j] <= 10^3
* 0 <= d <= 100
* */
public class _1385 {
public static class Solution1 {
public int findTheDistanceValue(int[] arr1, int[] arr2, int d) {
int count = 0;
for (int i = 0; i < arr1.length; i++) {
int j = 0;
for (; j < arr2.length; j++) {
if (Math.abs(arr1[i] - arr2[j]) <= d) {
break;
}
}
if (j == arr2.length) {
count++;
}
}
return count;
}
}
}