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_1019.java
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package com.fishercoder.solutions;
import com.fishercoder.common.classes.ListNode;
/**
* 1019. Next Greater Node In Linked List
*
* We are given a linked list with head as the first node. Let's number the nodes in the list: node_1, node_2, node_3, ... etc.
* Each node may have a next larger value: for node_i, next_larger(node_i) is the node_j.val such that j > i, node_j.val > node_i.val,
* and j is the smallest possible choice. If such a j does not exist, the next larger value is 0.
* Return an array of integers answer, where answer[i] = next_larger(node_{i+1}).
* Note that in the example inputs (not outputs) below, arrays such as [2,1,5] represent the serialization of a linked list
* with a head node value of 2, second node value of 1, and third node value of 5.
*
* Example 1:
* Input: [2,1,5]
* Output: [5,5,0]
*
* Example 2:
* Input: [2,7,4,3,5]
* Output: [7,0,5,5,0]
*
* Example 3:
* Input: [1,7,5,1,9,2,5,1]
* Output: [7,9,9,9,0,5,0,0]
*
* Note:
* 1 <= node.val <= 10^9 for each node in the linked list.
* The given list has length in the range [0, 10000].
* */
public class _1019 {
public static class Solution1 {
public int[] nextLargerNodes(ListNode head) {
int len = findLength(head);
int[] result = new int[len];
ListNode tmp = head;
int i = 0;
while (tmp != null) {
result[i++] = findNextLarger(tmp.val, tmp);
tmp = tmp.next;
}
return result;
}
private int findNextLarger(int val, ListNode head) {
ListNode tmp = head.next;
while (tmp != null) {
if (tmp.val > val) {
return tmp.val;
}
tmp = tmp.next;
}
return 0;
}
private int findLength(ListNode head) {
ListNode tmp = head;
int count = 0;
while (tmp != null) {
tmp = tmp.next;
count++;
}
return count;
}
}
}