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compare-version-numbers.js
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/**
* Source: https://leetcode.com/problems/compare-version-numbers/
* Tags: [String]
* Level: Easy
* Updated: 2015-04-24
* Title: Compare Version Numbers
* Auther: @imcoddy
* Content: Compare two version numbers version1 and version2.
* If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
*
* You may assume that the version strings are non-empty and contain only digits and the . character.
* The . character does not represent a decimal point and is used to separate number sequences.
* For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
*
* Here is an example of version numbers ordering:
* 0.1 < 1.1 < 1.2 < 13.37
*
* Credits:Special thanks to @ts for adding this problem and creating all test cases.
*/
/**
* @param {string} version1
* @param {string} version2
* @return {number}
*/
var compareVersion = function(version1, version2) {
if (!(version1 && version2)) {
return 0;
}
var v1 = version1.split('.');
var v2 = version2.split('.');
for (var i = 0; i < v1.length; i++) {
v1[i] = parseInt(v1[i], 10);
}
for (var i = 0; i < v2.length; i++) {
v2[i] = parseInt(v2[i], 10);
}
while (v1.length < v2.length) {
v1.push(0);
}
while (v2.length < v1.length) {
v2.push(0);
}
var index = 0;
while (index < v1.length) {
if (v1[index] > v2[index]) {
return 1;
} else if (v1[index] < v2[index]) {
return -1;
} else {
index++;
}
}
return 0;
};
console.log(compareVersion('1.1', '1.1'));
console.log(compareVersion('1.1.1', '1.1.2'));
console.log(compareVersion('1.1.0', '1.1'));
console.log(compareVersion('1.2', '1.13'));
console.log(compareVersion('1.3', '1.31'));
console.log(compareVersion('1.9', '1.31'));
console.log(compareVersion('1', '1.1'));
console.log(compareVersion('1', '1.0'));
console.log(compareVersion('2', '1.1'));