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No210.course-schedule-II.cs
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/*
* Difficulty:
* Medium
*
* Desc:
* There are a total of n courses you have to take, labeled from 0 to n-1.
* Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]
* Given the total number of courses and a list of prerequisite pairs, return the ordering of courses you should take to finish all courses.
* There may be multiple correct orders, you just need to return one of them. If it is impossible to finish all courses, return an empty array.
*
* Example 1:
* Input: 2, [[1,0]]
* Output: [0,1]
* Explanation:
* There are a total of 2 courses to take.
* To take course 1 you should have finished course 0. So the correct course order is [0,1] .
*
* Example 2:
* Input: 4, [[1,0],[2,0],[3,1],[3,2]]
* Output: [0,1,2,3] or [0,2,1,3]
* Explanation:
* There are a total of 4 courses to take.
* To take course 3 you should have finished both courses 1 and 2.
* Both courses 1 and 2 should be taken after you finished course 0.
* So one correct course order is [0,1,2,3]. Another correct ordering is [0,2,1,3] .
*
* Note:
* The input prerequisites is a graph represented by a list of edges, not adjacency matrices. Read more about how a graph is represented.
* You may assume that there are no duplicate edges in the input prerequisites.
*/
public class Solution {
public int[] FindOrder(int numCourses, int[][] prerequisites) {
HashSet<int> courses = new HashSet<int>(
Enumerable.Range(0, numCourses)
);
Dictionary<int, List<int>> dict = new Dictionary<int, List<int>>();
HashSet<int> visited = new HashSet<int>();
foreach (int[] prerequire in prerequisites) {
if (!dict.ContainsKey(prerequire[1])) dict[prerequire[1]] = new List<int>();
dict[prerequire[1]].Add(prerequire[0]);
courses.Remove(prerequire[0]);
courses.Remove(prerequire[1]);
}
Stack<int> path = new Stack<int>(courses);
bool dfs (int course, HashSet<int> marked) {
if (visited.Contains(course)) return true;
visited.Add(course);
marked.Add(course);
if (dict.ContainsKey(course)) {
foreach (int next in dict[course]) {
if (marked.Contains(next)) return false;
bool res = dfs(next, marked);
if (!res) return false;
}
}
path.Push(course);
marked.Remove(course);
return true;
}
foreach (int course in dict.Keys) {
if (visited.Contains(course)) continue;
bool res = dfs(course, new HashSet<int>());
if (!res) return new int[0];
}
return path.ToArray();
}
}