-
Notifications
You must be signed in to change notification settings - Fork 29
/
Copy pathNo1089.duplicate-zeros.cs
48 lines (46 loc) · 1.27 KB
/
No1089.duplicate-zeros.cs
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
/*
* Difficulty:
* Easy
*
* Desc:
* Given a fixed length array arr of integers, duplicate each occurrence of zero, shifting the remaining elements to the right.
* Note that elements beyond the length of the original array are not written.
* Do the above modifications to the input array in place, do not return anything from your function.
*
* Example 1:
* Input: [1,0,2,3,0,4,5,0]
* Output: null
* Explanation: After calling your function, the input array is modified to: [1,0,0,2,3,0,0,4]
*
* Example 2:
* Input: [1,2,3]
* Output: null
* Explanation: After calling your function, the input array is modified to: [1,2,3]
*
* Note:
* 1 <= arr.length <= 10000
* 0 <= arr[i] <= 9
*/
public class Solution {
public void DuplicateZeros(int[] arr) {
int count = 0;
int i = 0;
while (i < arr.Length) {
count += 1;
if (arr[i] == 0) count += 1;
if (count >= arr.Length) break;
i += 1;
}
int j = arr.Length - 1;
while (j >= 0) {
if (arr[i] != 0) {
arr[j] = arr[i];
} else {
arr[j] = 0;
if (count == arr.Length || j < arr.Length - 1) arr[--j] = 0;
}
j -= 1;
i -= 1;
}
}
}