-
Notifications
You must be signed in to change notification settings - Fork 29
/
Copy pathNo101.symmetric-tree.cs
46 lines (43 loc) · 1.08 KB
/
No101.symmetric-tree.cs
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
/*
* Difficulty:
* Easy
*
* Desc:
* Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
* For example, this binary tree [1,2,2,3,4,4,3] is symmetric:
* 1
* / \
* 2 2
* / \ / \
* 3 4 4 3
*
* But the following [1,2,2,null,3,null,3] is not:
* 1
* / \
* 2 2
* \ \
* 3 3
*
* Follow up: Solve it both recursively and iteratively.
*/
/**
* Definition for a binary tree node.
* public class TreeNode {
* public int val;
* public TreeNode left;
* public TreeNode right;
* public TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public bool IsSymmetric(TreeNode root) {
if (root == null) return true;
bool Check (TreeNode left, TreeNode right) {
if (left == null && right == null) return true;
if (left == null || right == null) return false;
if (left.val != right.val) return false;
return Check(left.left, right.right) && Check(left.right, right.left);
}
return Check(root.left, root.right);
}
}